To find the probability of obtaining a head when tossing a coin and rolling a 6 on a number cube (which has the numbers 1 through 6), we can follow these steps:
-
Probability of tossing a head: A coin has 2 sides (heads and tails), so the probability of getting a head is: \[ P(\text{Head}) = \frac{1}{2} \]
-
Probability of rolling a 6: A standard number cube (die) has 6 faces, so the probability of rolling a 6 is: \[ P(6) = \frac{1}{6} \]
-
Combine the probabilities: The events of tossing the coin and rolling the die are independent, so we multiply their probabilities to find the probability of both occurring: \[ P(\text{Head and 6}) = P(\text{Head}) \times P(6) = \frac{1}{2} \times \frac{1}{6} = \frac{1}{12} \]
-
Convert to decimal: To express \(\frac{1}{12}\) as a decimal: \[ \frac{1}{12} \approx 0.0833 \]
-
Round to the nearest hundredth: Rounding \(0.0833\) to the nearest hundredth gives: \[ 0.08 \]
Thus, the final answer is: \[ \boxed{0.08} \]