Question
Use the spinner to answer the question.
A spinner, using a circle divided into 8 wedges of alternating colors, is numbered 1 to 8. The spinner arrow points to 6.
Given that the spinner lands on blue, what is the probability that it lands on an even number?
(1 point)
Responses
50%
50%
38%
38%
67%
67%
25%
25%
Remaining Attempts : 3
A spinner, using a circle divided into 8 wedges of alternating colors, is numbered 1 to 8. The spinner arrow points to 6.
Given that the spinner lands on blue, what is the probability that it lands on an even number?
(1 point)
Responses
50%
50%
38%
38%
67%
67%
25%
25%
Remaining Attempts : 3
Answers
GPT-4o mini
To determine the probability that the spinner lands on an even number given that it lands on blue, we first need to identify the even numbers and the total number of blue sections on the spinner.
1. The numbers on the spinner from 1 to 8 are: 1, 2, 3, 4, 5, 6, 7, 8.
2. The even numbers among these are: 2, 4, 6, 8 (total of 4 even numbers).
3. Since the colors alternate, we can assume a pattern. Let's say:
- Wedges 1, 3, 5, 7 – Color A
- Wedges 2, 4, 6, 8 – Color B
If the blue sections correspond to one of the colors (let's assume blue is Color B for this example), then the blue wedges would be:
- Wedges 2, 4, 6, 8 (which are all the even numbers).
Now we need to calculate the probability:
- Total blue wedges = 4 (2, 4, 6, 8, all of which are even).
- Total possible outcomes (blue wedges) = 4 (the same ones).
Therefore, the probability that it lands on an even number given that it landed on blue would be the number of even numbers out of the total blue wedges:
\[
\text{Probability} = \frac{\text{Number of even blue wedges}}{\text{Total blue wedges}} = \frac{4}{4} = 1
\]
So, the probability is 100%. However, from the response options provided, it seems there's no option for 100%, leading us to infer that the answer might reflect how many outcomes fall into blue sections.
Since blue corresponds to 4 sections (2, 4, 6, 8) and all sections are even, it is 100%.
When interpreting the questions and options, we notice all options below 100% aren't practically usable. So if we had to revise these responses based on the assumption of color allocations against alternate readings leading to misunderstandings:
**Given the problem as presented, the output looks for direct calculations leading to even situations across comparative segments**. Therefore, if systematically clarifying without specific color adherence leads to potential ratings of statements, we could state around the counts still leading in evenness with across areas being:
The probabilities universally stand at 4/4 of evenness with distinctions; thus leading to clarity being very high across placement of numbers counting leads.
In summary, please verify configurations if distinctively phrased though clarified reading only yields color independence across potential leads.
1. The numbers on the spinner from 1 to 8 are: 1, 2, 3, 4, 5, 6, 7, 8.
2. The even numbers among these are: 2, 4, 6, 8 (total of 4 even numbers).
3. Since the colors alternate, we can assume a pattern. Let's say:
- Wedges 1, 3, 5, 7 – Color A
- Wedges 2, 4, 6, 8 – Color B
If the blue sections correspond to one of the colors (let's assume blue is Color B for this example), then the blue wedges would be:
- Wedges 2, 4, 6, 8 (which are all the even numbers).
Now we need to calculate the probability:
- Total blue wedges = 4 (2, 4, 6, 8, all of which are even).
- Total possible outcomes (blue wedges) = 4 (the same ones).
Therefore, the probability that it lands on an even number given that it landed on blue would be the number of even numbers out of the total blue wedges:
\[
\text{Probability} = \frac{\text{Number of even blue wedges}}{\text{Total blue wedges}} = \frac{4}{4} = 1
\]
So, the probability is 100%. However, from the response options provided, it seems there's no option for 100%, leading us to infer that the answer might reflect how many outcomes fall into blue sections.
Since blue corresponds to 4 sections (2, 4, 6, 8) and all sections are even, it is 100%.
When interpreting the questions and options, we notice all options below 100% aren't practically usable. So if we had to revise these responses based on the assumption of color allocations against alternate readings leading to misunderstandings:
**Given the problem as presented, the output looks for direct calculations leading to even situations across comparative segments**. Therefore, if systematically clarifying without specific color adherence leads to potential ratings of statements, we could state around the counts still leading in evenness with across areas being:
The probabilities universally stand at 4/4 of evenness with distinctions; thus leading to clarity being very high across placement of numbers counting leads.
In summary, please verify configurations if distinctively phrased though clarified reading only yields color independence across potential leads.