To calculate the surface area of the rectangular pyramid, we need to determine the area of the base and the area of the four triangular lateral faces.
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Area of the rectangular base:
- Length = 20 cm
- Width = 18 cm
- Area of the base = Length × Width = 20 cm × 18 cm = 360 cm²
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Area of the triangular lateral faces: We have two pairs of triangular faces:
- Two triangles with base 20 cm (length of the base) and height 17.2 cm (perpendicular height).
- Two triangles with base 18 cm (width of the base) and height 16.6 cm (perpendicular height).
Calculating the area of the two triangles with a base of 20 cm:
- Area of one triangle = (1/2) × base × height = (1/2) × 20 cm × 17.2 cm = 10 cm × 17.2 cm = 172 cm².
- Area of two triangles = 2 × 172 cm² = 344 cm².
Calculating the area of the two triangles with a base of 18 cm:
- Area of one triangle = (1/2) × base × height = (1/2) × 18 cm × 16.6 cm = 9 cm × 16.6 cm = 149.4 cm².
- Area of two triangles = 2 × 149.4 cm² = 298.8 cm².
- Total surface area of the pyramid:
- Total area = Area of the base + Area of the triangular faces = 360 cm² + 344 cm² + 298.8 cm² = 1002.8 cm².
After verifying the calculations:
- The total surface area is approximately 1002.8 cm².
None of the given responses match this value exactly, but the closest option provided is:
- 1,001.6 cm².
Thus, the correct answer is: 1,001.6 cm².