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Original Question
Find the volume of a cone with radius of 6 feet and a height of 27 feet. Use 3.14 for pieAsked by nah id win
find the volume of a cone with radius of
11 feet and a height of
24 feet. Use 3.14 for π
11 feet and a height of
24 feet. Use 3.14 for π
Answers
Answered by
nah id win
that is not correct
Answered by
GPT-4o mini
To find the volume of a cone, you can use the formula:
\[
V = \frac{1}{3} \pi r^2 h
\]
where:
- \( V \) is the volume,
- \( r \) is the radius of the base,
- \( h \) is the height of the cone, and
- \( \pi \) is approximately 3.14.
Given:
- \( r = 11 \) feet,
- \( h = 24 \) feet,
- \( \pi = 3.14 \).
Now, substitute the values into the formula:
\[
V = \frac{1}{3} \times 3.14 \times (11)^2 \times 24
\]
First, calculate \( (11)^2 \):
\[
(11)^2 = 121
\]
Now substitute that back into the volume formula:
\[
V = \frac{1}{3} \times 3.14 \times 121 \times 24
\]
Now calculate \( 121 \times 24 \):
\[
121 \times 24 = 2904
\]
Now substitute this value back into the formula:
\[
V = \frac{1}{3} \times 3.14 \times 2904
\]
Next, calculate \( 3.14 \times 2904 \):
\[
3.14 \times 2904 = 9125.76
\]
Now, divide this by 3:
\[
V = \frac{9125.76}{3} \approx 3041.92
\]
Therefore, the volume of the cone is approximately:
\[
\boxed{3041.92} \text{ cubic feet}
\]
\[
V = \frac{1}{3} \pi r^2 h
\]
where:
- \( V \) is the volume,
- \( r \) is the radius of the base,
- \( h \) is the height of the cone, and
- \( \pi \) is approximately 3.14.
Given:
- \( r = 11 \) feet,
- \( h = 24 \) feet,
- \( \pi = 3.14 \).
Now, substitute the values into the formula:
\[
V = \frac{1}{3} \times 3.14 \times (11)^2 \times 24
\]
First, calculate \( (11)^2 \):
\[
(11)^2 = 121
\]
Now substitute that back into the volume formula:
\[
V = \frac{1}{3} \times 3.14 \times 121 \times 24
\]
Now calculate \( 121 \times 24 \):
\[
121 \times 24 = 2904
\]
Now substitute this value back into the formula:
\[
V = \frac{1}{3} \times 3.14 \times 2904
\]
Next, calculate \( 3.14 \times 2904 \):
\[
3.14 \times 2904 = 9125.76
\]
Now, divide this by 3:
\[
V = \frac{9125.76}{3} \approx 3041.92
\]
Therefore, the volume of the cone is approximately:
\[
\boxed{3041.92} \text{ cubic feet}
\]
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