To calculate the volume of a sphere, you can use the formula:
\[ V = \frac{4}{3} \pi r^3 \]
You didn't provide a radius, but if we assume common radii, we can compute the volume accordingly.
-
If we let \( r = 5 \) ft: \[ V = \frac{4}{3} \times 3.14 \times 5^3 = \frac{4}{3} \times 3.14 \times 125 = \frac{4}{3} \times 392.5 \approx 523.3 , \text{ft}^3 \]
-
If we let \( r = 3 \) ft: \[ V = \frac{4}{3} \times 3.14 \times 3^3 = \frac{4}{3} \times 3.14 \times 27 = \frac{4}{3} \times 84.78 \approx 113.0 , \text{ft}^3 \]
-
If we let \( r = 2 \) ft: \[ V = \frac{4}{3} \times 3.14 \times 2^3 = \frac{4}{3} \times 3.14 \times 8 = \frac{4}{3} \times 25.12 \approx 33.5 , \text{ft}^3 \]
-
If we let \( r = 1 \) ft: \[ V = \frac{4}{3} \times 3.14 \times 1^3 = \frac{4}{3} \times 3.14 \times 1 = \frac{4}{3} \times 3.14 \approx 4.2 , \text{ft}^3 \]
It appears that the value that closely matches any of the given answers when using a radius of 5 ft is the volume of 523.3 ft³.
Thus, the volume of the sphere rounded to the nearest tenth is:
523.3 ft.³.