To calculate the volume of a spherical piñata, we use the formula for the volume of a sphere:
\[ V = \frac{4}{3} \pi r^3 \]
Where \( V \) is the volume and \( r \) is the radius.
Given that the diameter of the piñata is 18 inches, the radius \( r \) is half of the diameter:
\[ r = \frac{18}{2} = 9 \text{ inches} \]
Now, substituting the radius and using \( \pi \approx 3.14 \):
\[ V = \frac{4}{3} \times 3.14 \times (9)^3 \]
Calculating \( 9^3 \):
\[ 9^3 = 729 \]
Now substituting this value back into the volume formula:
\[ V = \frac{4}{3} \times 3.14 \times 729 \]
Calculating \( \frac{4}{3} \times 3.14 \):
\[ \frac{4}{3} \times 3.14 \approx 4.1867 \]
Now multiplying this by 729:
\[ V \approx 4.1867 \times 729 \approx 3,055.3013 \]
Rounding this to the nearest tenth:
\[ V \approx 3,052.1 \text{ inches}^3 \]
Thus, the volume of the piñata is:
3,052.1 inches³