To calculate the volume of the creamy filling inside the chocolate sphere, we need to find the volume of the sphere. The formula for the volume \( V \) of a sphere is given by:
\[ V = \frac{4}{3} \pi r^3 \]
Where \( r \) is the radius of the sphere. Given that the diameter of the chocolate piece is 1 inch, the radius \( r \) is:
\[ r = \frac{1}{2} \text{ inch} = 0.5 \text{ inch} \]
Now we can plug the radius into the volume formula:
\[ V = \frac{4}{3} \pi (0.5)^3 \]
Calculating \( (0.5)^3 \):
\[ (0.5)^3 = 0.125 \]
Now substituting this back into the volume formula:
\[ V = \frac{4}{3} \pi (0.125) = \frac{4 \times 0.125}{3} \pi = \frac{0.5}{3} \pi = \frac{1}{6} \pi \]
To provide the answer in decimal form, we can approximate \( \pi \) as 3.14:
\[ V \approx \frac{1}{6} \times 3.14 \approx 0.5233 \]
Rounding to the nearest tenth:
\[ V \approx 0.5 \]
Thus, the volume of the creamy filling that can fit inside the chocolate piece is:
\[ \frac{1}{6} \pi \text{ inches}^3 \quad \text{or approximately} \quad 0.5 \text{ inches}^3. \]