Asked by stinkybooty
Now, divide both sides by 8π to get r
2
alone on the right side of the equation.
r=?Area Label Arrow
height = 8
Volume = 32π
Volume
=
Area of base ⋅ Height
V
=
πr
2
·h
32π
=
π · r
2
· 8
32π
=
8π·r
2
8π
8π
=
2
alone on the right side of the equation.
r=?Area Label Arrow
height = 8
Volume = 32π
Volume
=
Area of base ⋅ Height
V
=
πr
2
·h
32π
=
π · r
2
· 8
32π
=
8π·r
2
8π
8π
=
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To solve for \( r^2 \), you start with the equation:
\[
32\pi = 8\pi \cdot r^2
\]
Now, you need to divide both sides by \( 8\pi \):
\[
\frac{32\pi}{8\pi} = r^2
\]
The \( \pi \) in the numerator and denominator cancels out:
\[
\frac{32}{8} = r^2
\]
Calculating the left side gives:
\[
4 = r^2
\]
Now, to find \( r \), take the square root of both sides:
\[
r = \sqrt{4}
\]
Thus,
\[
r = 2
\]
So, the final answer is:
\[
r = 2
\]
\[
32\pi = 8\pi \cdot r^2
\]
Now, you need to divide both sides by \( 8\pi \):
\[
\frac{32\pi}{8\pi} = r^2
\]
The \( \pi \) in the numerator and denominator cancels out:
\[
\frac{32}{8} = r^2
\]
Calculating the left side gives:
\[
4 = r^2
\]
Now, to find \( r \), take the square root of both sides:
\[
r = \sqrt{4}
\]
Thus,
\[
r = 2
\]
So, the final answer is:
\[
r = 2
\]
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