Question

In a wall outlet with a resistance of 3.7 ohms and a voltage of 110V, what is the current flowing into the outlet?

(1 point)

Ο 407.0 A

113.7 A

29.7 A

0.04 A

Answer 1

To find the current flowing into the outlet, you can use Ohm's Law, which states:

\[ I = \frac{V}{R} \]

where:
- \( I \) is the current in amperes,
- \( V \) is the voltage in volts,
- \( R \) is the resistance in ohms.

Given:
- \( V = 110 \, \text{V} \)
- \( R = 3.7 \, \Omega \)

Now plug the values into the formula:

\[ I = \frac{110\,\text{V}}{3.7\,\Omega} \]

Calculating this gives:

\[ I \approx 29.73 \, \text{A} \]

Rounding appropriately, we find:

\[ I \approx 29.7 \, \text{A} \]

So, the correct answer is **29.7 A**.