sure you do. The given line has slope 1/3 and passes through (5,-2).
You want a line with slope -3 that passes through (-4,3).
y-3 = -3(x+4)
y = -3x -9
(B)
39. Write the equation of a line that is perpendicular to the given line and that passes through the given point.
y + 2 = 1/3(x – 5); (–4, 3)
A.)y = –3x + 15
B.)y = –3x – 9
C.)y = –4x + 3
D.)y = –1/3x – 11
I don't know how to do this.
1 answer