If BO = 45 in and BA = 108 in then what is the length of AO to the nearest whole inch? Use Pythagorean theorem

1 answer

To find the length of AO using the Pythagorean theorem, we can consider triangle AOB, where:

  • BO is one leg of the triangle = 45 inches
  • BA is the other leg of the triangle = 108 inches
  • AO is the hypotenuse of the triangle

According to the Pythagorean theorem:

\[ AO^2 = AB^2 + BO^2 \]

Substituting the values we have:

\[ AO^2 = 108^2 + 45^2 \]

Calculating each square:

\[ 108^2 = 11664 \] \[ 45^2 = 2025 \]

Now, sum the squares:

\[ AO^2 = 11664 + 2025 = 13689 \]

Taking the square root to find AO:

\[ AO = \sqrt{13689} \approx 117 \]

Thus, the length of AO to the nearest whole inch is 117 inches.