Question
To find the volume of this cylinder, we need to multiply π · 25 by 3. Start by multiplying 25 ⋅ 3.
5 ftArea Label Arrow
3 ft
25π ft
2
V
=
B
⋅
H
Volume
=
Area of base
⋅
Height
=
πr
2
⋅
3
=
π · 25
⋅
3
=
π ⋅
5 ftArea Label Arrow
3 ft
25π ft
2
V
=
B
⋅
H
Volume
=
Area of base
⋅
Height
=
πr
2
⋅
3
=
π · 25
⋅
3
=
π ⋅
Answers
GPT-4o mini
To find the volume of the cylinder, we can follow these steps:
1. **Calculate the base area of the cylinder**: The base area \( B \) of a cylinder is given by the formula for the area of a circle, \( B = \pi r^2 \), where \( r \) is the radius of the base. In this case, the radius given is 5 ft.
\[
B = \pi (5)^2 = \pi (25) = 25\pi \, \text{ft}^2
\]
2. **Multiply the base area by the height**: The height \( H \) of the cylinder is 3 ft. The volume \( V \) is calculated as:
\[
V = B \cdot H = 25\pi \cdot 3
\]
Now, multiply \( 25 \) by \( 3 \):
\[
25 \cdot 3 = 75
\]
3. **Substitute back into the volume formula**:
\[
V = 75\pi \, \text{ft}^3
\]
So the volume of the cylinder is:
\[
V = 75\pi \, \text{ft}^3
\]
If you need a numerical approximation, using \( \pi \approx 3.14 \):
\[
V \approx 75 \cdot 3.14 \approx 235.5 \, \text{ft}^3
\]
Therefore, the final answer for the volume is:
\[
V = 75\pi \, \text{ft}^3 \quad \text{or approximately} \quad 235.5 \, \text{ft}^3
\]
1. **Calculate the base area of the cylinder**: The base area \( B \) of a cylinder is given by the formula for the area of a circle, \( B = \pi r^2 \), where \( r \) is the radius of the base. In this case, the radius given is 5 ft.
\[
B = \pi (5)^2 = \pi (25) = 25\pi \, \text{ft}^2
\]
2. **Multiply the base area by the height**: The height \( H \) of the cylinder is 3 ft. The volume \( V \) is calculated as:
\[
V = B \cdot H = 25\pi \cdot 3
\]
Now, multiply \( 25 \) by \( 3 \):
\[
25 \cdot 3 = 75
\]
3. **Substitute back into the volume formula**:
\[
V = 75\pi \, \text{ft}^3
\]
So the volume of the cylinder is:
\[
V = 75\pi \, \text{ft}^3
\]
If you need a numerical approximation, using \( \pi \approx 3.14 \):
\[
V \approx 75 \cdot 3.14 \approx 235.5 \, \text{ft}^3
\]
Therefore, the final answer for the volume is:
\[
V = 75\pi \, \text{ft}^3 \quad \text{or approximately} \quad 235.5 \, \text{ft}^3
\]