To compare the average deviations of the two datasets, we need to calculate the average deviation for each table.
Table 1
Distance from Mean: 0, 4, 2, 1, 0, 1, 1, 1, 2
Total Distance: 0 + 4 + 2 + 1 + 0 + 1 + 1 + 1 + 2 = 12
Number of Data Points: 9
Average Deviation: \( \frac{12}{9} = \frac{4}{3} \approx 1.33 \)
Table 2
Distance from Mean: 2, 1, 3, 3, 1, 1, 1, 1, 2
Total Distance: 2 + 1 + 3 + 3 + 1 + 1 + 1 + 1 + 2 = 15
Number of Data Points: 9
Average Deviation: \( \frac{15}{9} = \frac{5}{3} \approx 1.67 \)
Comparison
- Average Deviation of Table 1: \( \approx 1.33 \)
- Average Deviation of Table 2: \( \approx 1.67 \)
Conclusion
The second table has a larger average deviation than the first table.
So, the correct response is: The second table has a larger average deviation.