Question

What is the area of a trapezoid that has a base length of 13 in., a base length of 7 in., and a height of 12 in.?(1 point)
in.2

Answer 1

To find the area of a trapezoid, you can use the formula:

\[
\text{Area} = \frac{1}{2} \times (b_1 + b_2) \times h
\]

where \(b_1\) and \(b_2\) are the lengths of the two bases, and \(h\) is the height.

Given:
- \(b_1 = 13\) in.
- \(b_2 = 7\) in.
- \(h = 12\) in.

Now plug in the values:

\[
\text{Area} = \frac{1}{2} \times (13 + 7) \times 12
\]

First, calculate \(b_1 + b_2\):

\[
13 + 7 = 20
\]

Then multiply by the height and divide by 2:

\[
\text{Area} = \frac{1}{2} \times 20 \times 12
\]

Calculating this:

\[
\text{Area} = 10 \times 12 = 120
\]

Thus, the area of the trapezoid is \(120\) in².