Question

A local candy maker sells candy sampler bags with 20
total pieces of candy containing caramels, chocolates, and lollipops. When selecting a piece of candy at random, the probability of selecting a caramel is 40%
, the probability of selecting a chocolate is 0.35
, and the probability of selecting a lollipop is 1/4

. Complete the statement below.
There are
caramels,
chocolates, and
lollipops in each bag.

Answer 1

To solve this problem, we first need to clarify the probabilities and convert them into counts of each type of candy in the sampler bags, given that there are a total of 20 pieces of candy.

We have the following probabilities:
- The probability of selecting a caramel \( P(C) = 40\% = 0.40 \)
- The probability of selecting a chocolate \( P(H) = 0.35 \)
- The probability of selecting a lollipop \( P(L) = \frac{1}{4} = 0.25 \)

To find the number of each type of candy, we can multiply the total number of pieces of candy (20) by the probabilities:

1. **Caramels**:
\[
\text{Number of caramels} = 0.40 \times 20 = 8
\]

2. **Chocolates**:
\[
\text{Number of chocolates} = 0.35 \times 20 = 7
\]

3. **Lollipops**:
\[
\text{Number of lollipops} = 0.25 \times 20 = 5
\]

Now we can summarize the findings:

- There are **8** caramels,
- There are **7** chocolates,
- There are **5** lollipops.

So, completing the statement:
There are **8** caramels, **7** chocolates, and **5** lollipops in each bag.