Question
Calculate the volume of the sphere with a height of 12cm.. Use 3.14 for pi and round to the nearest tenth.
Answers
Answered by
GPT-4o mini
To find the volume of a sphere, we use the formula:
\[
V = \frac{4}{3} \pi r^3
\]
where \( r \) is the radius of the sphere.
From the problem, the height of the sphere is given as 12 cm. The height of a sphere is equal to its diameter, so we can find the radius:
\[
\text{Diameter} = 12 \, \text{cm} \implies r = \frac{\text{Diameter}}{2} = \frac{12}{2} = 6 \, \text{cm}
\]
Now we can substitute the radius into the volume formula:
\[
V = \frac{4}{3} \times 3.14 \times (6)^3
\]
First, we calculate \( (6)^3 \):
\[
(6)^3 = 6 \times 6 \times 6 = 216
\]
Now substitute that value into the volume formula:
\[
V = \frac{4}{3} \times 3.14 \times 216
\]
Calculating \( \frac{4}{3} \times 216 \):
\[
\frac{4 \times 216}{3} = \frac{864}{3} = 288
\]
So now we can find the volume:
\[
V = 3.14 \times 288
\]
Calculating \( 3.14 \times 288 \):
\[
V = 903.92
\]
Now rounding to the nearest tenth, we find:
\[
V \approx 903.9 \, \text{cm}^3
\]
Thus, the volume of the sphere is approximately \( \boxed{903.9} \, \text{cm}^3 \).
\[
V = \frac{4}{3} \pi r^3
\]
where \( r \) is the radius of the sphere.
From the problem, the height of the sphere is given as 12 cm. The height of a sphere is equal to its diameter, so we can find the radius:
\[
\text{Diameter} = 12 \, \text{cm} \implies r = \frac{\text{Diameter}}{2} = \frac{12}{2} = 6 \, \text{cm}
\]
Now we can substitute the radius into the volume formula:
\[
V = \frac{4}{3} \times 3.14 \times (6)^3
\]
First, we calculate \( (6)^3 \):
\[
(6)^3 = 6 \times 6 \times 6 = 216
\]
Now substitute that value into the volume formula:
\[
V = \frac{4}{3} \times 3.14 \times 216
\]
Calculating \( \frac{4}{3} \times 216 \):
\[
\frac{4 \times 216}{3} = \frac{864}{3} = 288
\]
So now we can find the volume:
\[
V = 3.14 \times 288
\]
Calculating \( 3.14 \times 288 \):
\[
V = 903.92
\]
Now rounding to the nearest tenth, we find:
\[
V \approx 903.9 \, \text{cm}^3
\]
Thus, the volume of the sphere is approximately \( \boxed{903.9} \, \text{cm}^3 \).