To determine the similarity between triangles \( \triangle ABC \) and \( \triangle GHJ \), we first need to find the measure of angle \( C \) using the fact that the sum of the angles in a triangle is \( 180^\circ \).
For triangle \( ABC \):
- \( m\angle A = 47^\circ \)
- \( m\angle B = 36^\circ \)
- Therefore, \( m\angle C = 180^\circ - (47^\circ + 36^\circ) = 180^\circ - 83^\circ = 97^\circ \).
Now, let's list the angles of triangle \( GHJ \):
- \( m\angle G = 36^\circ \)
- \( m\angle J = 97^\circ \)
Since \( m\angle B = 36^\circ \), \( m\angle C = 97^\circ \), and \( m\angle A = 47^\circ \) hasn't been addressed in triangle \( GHJ \) yet, we need to find \( m\angle H \):
- \( m\angle H = 180^\circ - (m\angle G + m\angle J) = 180^\circ - (36^\circ + 97^\circ) = 180^\circ - 133^\circ = 47^\circ \).
Now we can see:
-
\( m\angle A = 47^\circ \)
-
\( m\angle B = 36^\circ \)
-
\( m\angle C = 97^\circ \)
-
\( m\angle G = 36^\circ \)
-
\( m\angle H = 47^\circ \)
-
\( m\angle J = 97^\circ \)
Since both triangles \( \triangle ABC \) and \( \triangle GHJ \) have the same angles, we can conclude:
\[ \triangle ABC \sim \triangle GHJ \]
The correct response is:
△ABC∼△GHJ