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What would the approximate diagonal through the cylinder be in inches if the radius of the cylinder is 7 inches and the height...Asked by Slim Shady
What would the approximate diagonal through the cylinder be in inches if the radius of the cylinder is 7 inches and the height of the cylinder is 12 inches?
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(4 points)
Put responses in the correct input to answer the question. Select a response, navigate to the desired input and insert the response. Responses can be selected and inserted using the space bar, enter key, left mouse button or touchpad. Responses can also be moved by dragging with a mouse.
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Answered by
GPT-4o mini
To calculate the approximate diagonal through the cylinder, we can use the Pythagorean theorem in three dimensions. The diagonal \(d\) can be found using the formula:
\[
d = \sqrt{h^2 + (2r)^2}
\]
where:
- \(h\) is the height of the cylinder,
- \(r\) is the radius of the cylinder.
Given:
- Height \(h = 12\) inches,
- Radius \(r = 7\) inches.
Now we can input these values into the formula:
\[
d = \sqrt{12^2 + (2 \times 7)^2}
\]
\[
d = \sqrt{12^2 + 14^2}
\]
\[
d = \sqrt{144 + 196}
\]
\[
d = \sqrt{340}
\]
\[
d \approx 18.44 \text{ inches}
\]
Therefore, the approximate diagonal through the cylinder is **18.44 inches**.
\[
d = \sqrt{h^2 + (2r)^2}
\]
where:
- \(h\) is the height of the cylinder,
- \(r\) is the radius of the cylinder.
Given:
- Height \(h = 12\) inches,
- Radius \(r = 7\) inches.
Now we can input these values into the formula:
\[
d = \sqrt{12^2 + (2 \times 7)^2}
\]
\[
d = \sqrt{12^2 + 14^2}
\]
\[
d = \sqrt{144 + 196}
\]
\[
d = \sqrt{340}
\]
\[
d \approx 18.44 \text{ inches}
\]
Therefore, the approximate diagonal through the cylinder is **18.44 inches**.
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