Question
what is the theoretical probability of of rolling a number divisible by 3 on a 15 fair sided die rounded to the nearest tenth
Answers
GPT-4o mini
To find the theoretical probability of rolling a number divisible by 3 on a 15-sided die, we first need to determine how many of the possible outcomes (the numbers 1 through 15) are divisible by 3.
The numbers from 1 to 15 that are divisible by 3 are:
- 3
- 6
- 9
- 12
- 15
So, there are 5 numbers (3, 6, 9, 12, and 15) that meet this condition.
The total number of possible outcomes when rolling a 15-sided die is 15.
The probability \( P \) of rolling a number divisible by 3 is given by the formula:
\[
P = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} = \frac{5}{15}
\]
Simplifying this fraction gives:
\[
P = \frac{1}{3}
\]
To express this probability as a decimal, we calculate:
\[
\frac{1}{3} \approx 0.3333
\]
When rounding to the nearest tenth, this becomes:
\[
0.3
\]
Thus, the theoretical probability of rolling a number divisible by 3 on a 15-sided die, rounded to the nearest tenth, is **0.3**.
The numbers from 1 to 15 that are divisible by 3 are:
- 3
- 6
- 9
- 12
- 15
So, there are 5 numbers (3, 6, 9, 12, and 15) that meet this condition.
The total number of possible outcomes when rolling a 15-sided die is 15.
The probability \( P \) of rolling a number divisible by 3 is given by the formula:
\[
P = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} = \frac{5}{15}
\]
Simplifying this fraction gives:
\[
P = \frac{1}{3}
\]
To express this probability as a decimal, we calculate:
\[
\frac{1}{3} \approx 0.3333
\]
When rounding to the nearest tenth, this becomes:
\[
0.3
\]
Thus, the theoretical probability of rolling a number divisible by 3 on a 15-sided die, rounded to the nearest tenth, is **0.3**.