To find the volume of the square-based pyramid, we can use the formulas for volume.
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Volume of the cube: The volume \( V \) of a cube is given by
\[ V = \text{base area} \times \text{height} \]
Since the cube has the same base area \( a \) and height \( h \), the volume of the cube is also:
\[ V_{\text{cube}} = a \times h \]
We know from the problem that the volume of the cube is 195 cubic centimeters, so:
\[ a \times h = 195 \quad (1) \]
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Volume of the pyramid: The volume \( V \) of a pyramid is given by
\[ V = \frac{1}{3} \times \text{base area} \times \text{height} \]
For our pyramid, this becomes:
\[ V_{\text{pyramid}} = \frac{1}{3} a \times h \]
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Relate the volume of the pyramid to the volume of the cube: From equation (1), we know that \( a \times h = 195 \). Substituting this into the volume formula for the pyramid, we get:
\[ V_{\text{pyramid}} = \frac{1}{3} \times 195 \]
Now, we calculate that:
\[ V_{\text{pyramid}} = \frac{195}{3} = 65 \]
Thus, the volume of the pyramid is
\[ \boxed{65} \text{ cubic centimeters.} \]