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Original Question
Line p passes through points (8, 13) and (10, 4). Line q is parallel to line p. What is the slope of line q?Asked by xoxo_riri
Line c passes through points (-41, 72) and (13, 48). Line d is parallel to line c. What is the slope of line d?]
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Answered by
GPT-4o mini
To find the slope of line \(d\), which is parallel to line \(c\), we first need to calculate the slope of line \(c\) using the two given points \((-41, 72)\) and \((13, 48)\).
The formula for the slope \(m\) between two points \((x_1, y_1)\) and \((x_2, y_2)\) is given by:
\[
m = \frac{y_2 - y_1}{x_2 - x_1}
\]
Substituting the coordinates of the points into the formula where \((x_1, y_1) = (-41, 72)\) and \((x_2, y_2) = (13, 48)\):
\[
m = \frac{48 - 72}{13 - (-41)}
\]
\[
m = \frac{48 - 72}{13 + 41}
\]
\[
m = \frac{-24}{54}
\]
Now, simplify \(\frac{-24}{54}\):
\[
m = \frac{-4}{9}
\]
The slope of line \(c\) is \(-\frac{4}{9}\). Since line \(d\) is parallel to line \(c\), it will have the same slope.
Thus, the slope of line \(d\) is
\[
\boxed{-\frac{4}{9}}.
\]
The formula for the slope \(m\) between two points \((x_1, y_1)\) and \((x_2, y_2)\) is given by:
\[
m = \frac{y_2 - y_1}{x_2 - x_1}
\]
Substituting the coordinates of the points into the formula where \((x_1, y_1) = (-41, 72)\) and \((x_2, y_2) = (13, 48)\):
\[
m = \frac{48 - 72}{13 - (-41)}
\]
\[
m = \frac{48 - 72}{13 + 41}
\]
\[
m = \frac{-24}{54}
\]
Now, simplify \(\frac{-24}{54}\):
\[
m = \frac{-4}{9}
\]
The slope of line \(c\) is \(-\frac{4}{9}\). Since line \(d\) is parallel to line \(c\), it will have the same slope.
Thus, the slope of line \(d\) is
\[
\boxed{-\frac{4}{9}}.
\]
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