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Original Question
Line d passes through points (3, 5) and (8, 8). Line e is perpendicular to d. What is the slope of line e?Asked by xoxo_riri
Line f passes through points (2, 2) and (4, 9). Line g is perpendicular to f. What is the slope of line g?
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Answered by
GPT-4o mini
To determine the slope of line \( g \), we first need to find the slope of line \( f \). The slope \( m \) of a line that passes through points \((x_1, y_1)\) and \((x_2, y_2)\) is given by the formula:
\[
m = \frac{y_2 - y_1}{x_2 - x_1}
\]
For line \( f \), the points are \((2, 2)\) and \((4, 9)\).
Plugging in the points:
\[
m_f = \frac{9 - 2}{4 - 2} = \frac{7}{2}
\]
So, the slope of line \( f \) is \(\frac{7}{2}\).
Since line \( g \) is perpendicular to line \( f\), the slope of line \( g \) (denoted as \( m_g \)) is the negative reciprocal of the slope of line \( f \). The negative reciprocal is found by taking the negative of the reciprocal of \( m_f \):
\[
m_g = -\frac{1}{m_f} = -\frac{1}{\frac{7}{2}} = -\frac{2}{7}
\]
Thus, the slope of line \( g \) is
\[
\boxed{-\frac{2}{7}}.
\]
\[
m = \frac{y_2 - y_1}{x_2 - x_1}
\]
For line \( f \), the points are \((2, 2)\) and \((4, 9)\).
Plugging in the points:
\[
m_f = \frac{9 - 2}{4 - 2} = \frac{7}{2}
\]
So, the slope of line \( f \) is \(\frac{7}{2}\).
Since line \( g \) is perpendicular to line \( f\), the slope of line \( g \) (denoted as \( m_g \)) is the negative reciprocal of the slope of line \( f \). The negative reciprocal is found by taking the negative of the reciprocal of \( m_f \):
\[
m_g = -\frac{1}{m_f} = -\frac{1}{\frac{7}{2}} = -\frac{2}{7}
\]
Thus, the slope of line \( g \) is
\[
\boxed{-\frac{2}{7}}.
\]
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