The approximate number of zombies in a certain city over time is given in the table below. Answer the questions below to determine what kind of function would best fit the data, linear or exponential. Number of Hours Since Zombies First Spotted, x 11 22 33 44 Approx. Number of Zombies, f(x) 3333 5050 6767 8585 Answer function would best fit the data because as xx increases, the yy values change . Rounded to the nearest .5, the of this function is approximately

1 answer

To determine what kind of function best fits the given data, let's first observe the values provided in the table:

| Hours (x) | Zombies (f(x)) | |-----------|----------------| | 11 | 3333 | | 22 | 5050 | | 33 | 6767 | | 44 | 8585 |

Step 1: Check for Linear Growth

We can check whether the change in the number of zombies is constant, indicating a linear relationship.

  1. Calculate the change in zombies for each interval:
    • From 11 to 22 hours: \( 5050 - 3333 = 1717 \)
    • From 22 to 33 hours: \( 6767 - 5050 = 1717 \)
    • From 33 to 44 hours: \( 8585 - 6767 = 1718 \) (rounded difference)

The difference is approximately constant (around 1717), suggesting a linear relationship.

Step 2: Check for Exponential Growth

Next, we can check if the ratio of the changes indicates an exponential growth pattern:

  1. Calculate the ratios of the changes:
    • From 11 to 22 hours: \( \frac{5050}{3333} \approx 1.515 \)
    • From 22 to 33 hours: \( \frac{6767}{5050} \approx 1.339 \)
    • From 33 to 44 hours: \( \frac{8585}{6767} \approx 1.270 \)

The ratios are not constant, indicating that the relationship isn't exponential.

Conclusion

The function that best fits the data is linear because the number of zombies increases consistently over equal intervals of x (hours).

Step 3: Determine Linear Function

To find a linear function, we can use the format \( f(x) = mx + b \), where:

  • \( m \) is the slope
  • \( b \) is the y-intercept

Using two points, for example, (11, 3333) and (22, 5050), we can determine the slope (\( m \)): \[ m = \frac{(5050 - 3333)}{(22 - 11)} = \frac{1717}{11} \approx 156.09 \]

Now to find \( b \) using \( f(11) = 3333 \): \[ 3333 = 156.09 \cdot 11 + b \] \[ 3333 = 1717 + b \] \[ b \approx 1616 \]

Final Linear Function

So, the approximate linear function is: \[ f(x) \approx 156.09x + 1616 \]

Thus, the function would best fit the data because as \( x \) increases, the \( y \) values change linearly. Rounded to the nearest .5, the slope of this function is approximately 156.1.