Given that events A and B are independent with P(A))=0.32 and P(B)=0.95, determine the value of P(A∩B), rounding to the nearest thousandth, if necessary.(1 point)

1 answer

If events A and B are independent, the probability of both events occurring (the intersection of A and B, denoted as \( P(A \cap B) \)) can be calculated using the formula:

\[ P(A \cap B) = P(A) \times P(B) \]

Given \( P(A) = 0.32 \) and \( P(B) = 0.95 \), we can calculate:

\[ P(A \cap B) = 0.32 \times 0.95 \]

Calculating this gives:

\[ P(A \cap B) = 0.304 \]

Thus, rounding to the nearest thousandth, the value of \( P(A \cap B) \) is:

\[ \boxed{0.304} \]