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Maria has a set of 10 index cards labeled with the digits 0 through 9. She puts them in a bag and selects one at random. The outcome that is most likely to occur is selecting(1 point) Responses an odd number an odd number a prime number a prime number a number that is at most 5 a number that is at most 5 a number that is divisble by 3

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To determine the outcome that is most likely to occur when Maria selects a card at random from a set labeled with the digits 0 through 9, we will analyze each of the categories.

  1. Odd numbers: The odd numbers from 0 to 9 are 1, 3, 5, 7, and 9. There are 5 odd numbers.

  2. Prime numbers: The prime numbers from 0 to 9 are 2, 3, 5, and 7. There are 4 prime numbers.

  3. Numbers that are at most 5: The numbers that are at most 5 are 0, 1, 2, 3, 4, and 5. There are 6 numbers that meet this criterion.

  4. Numbers that are divisible by 3: The numbers that are divisible by 3 are 0, 3, 6, and 9. There are 4 numbers divisible by 3.

Now we can compare the counts:

  • Odd numbers: 5
  • Prime numbers: 4
  • Numbers that are at most 5: 6
  • Numbers divisible by 3: 4

The category with the highest count is "a number that is at most 5," which has 6 possibilities.

Therefore, the outcome that is most likely to occur is selecting a number that is at most 5.