Multiply.

StartFraction 8 s squared minus 57 s plus 7 Over 8 s squared plus 63 s minus 8 EndFraction
times StartFraction 7 s squared plus 55 s minus 8 Over 56 s squared minus 15 s plus 1 EndFraction
  
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Part 1
The simplified form is
  
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1 answer

To multiply the two fractions

\[ \frac{8s^2 - 57s + 7}{8s^2 + 63s - 8} \times \frac{7s^2 + 55s - 8}{56s^2 - 15s + 1}, \]

we can first focus on factoring each polynomial.

  1. Factoring the numerator \( 8s^2 - 57s + 7 \): \[ 8s^2 - 57s + 7 = (8s + 1)(s - 7) \] (This can be verified via expansion)

  2. Factoring the denominator \( 8s^2 + 63s - 8 \): \[ 8s^2 + 63s - 8 = (8s - 1)(s + 8) \] (This can also be verified via expansion)

  3. Factoring the numerator \( 7s^2 + 55s - 8 \): \[ 7s^2 + 55s - 8 = (7s - 1)(s + 8) \] (Verification via expansion is recommended)

  4. Factoring the denominator \( 56s^2 - 15s + 1 \): \[ 56s^2 - 15s + 1 = (7s - 1)(8s - 1) \] (Again, verification via expansion is recommended)

Now substituting all of these factors into the product gives:

\[ \frac{(8s + 1)(s - 7)}{(8s - 1)(s + 8)} \times \frac{(7s - 1)(s + 8)}{(7s - 1)(8s - 1)} \]

Next, we cancel the common factors:

  • We see \( (7s - 1) \) cancels from the numerator and denominator.
  • \( (s + 8) \) cancels from the numerator and denominator.
  • \( (8s - 1) \) cancels from the numerator and denominator.

After cancellation, we are left with:

\[ \frac{(8s + 1)(s - 7)}{1}. \]

This simplifies to:

\[ (8s + 1)(s - 7) \]

Expanding this product gives:

\[ 8s^2 - 56s + s - 7 = 8s^2 - 55s - 7. \]

Thus, the answer is:

\[ 8s^2 - 55s - 7. \]

The simplified form is \(\boxed{8s^2 - 55s - 7}\).