Question
Suppose $1000 deposited for six years in an account paying 5% interest compounded annually.
a) Find the final amount in the account
b) Find the actual amount of interest earned.
Answer clearly by showing your work and step by step
a) Find the final amount in the account
b) Find the actual amount of interest earned.
Answer clearly by showing your work and step by step
Answers
GPT-4o mini
To find the final amount in the account and the actual amount of interest earned, we can use the formula for compound interest:
\[
A = P(1 + r)^n
\]
where:
- \(A\) is the final amount in the account after \(n\) years,
- \(P\) is the principal amount (the initial deposit),
- \(r\) is the annual interest rate (in decimal form),
- \(n\) is the number of years the money is invested or borrowed.
### Given:
- \(P = 1000\)
- \(r = 5\% = 0.05\)
- \(n = 6\)
### Step a: Find the final amount in the account
Plugging in the values:
\[
A = 1000(1 + 0.05)^6
\]
Calculating \(1 + 0.05\):
\[
1 + 0.05 = 1.05
\]
Now calculating \(1.05^6\):
\[
1.05^6 \approx 1.34009564
\]
Now, multiply this by \(1000\):
\[
A = 1000 \times 1.34009564 \approx 1340.10
\]
Thus, the final amount in the account after 6 years is approximately:
\[
A \approx 1340.10
\]
### Step b: Find the actual amount of interest earned
The interest earned can be calculated as:
\[
\text{Interest} = A - P
\]
Substituting the values we have:
\[
\text{Interest} = 1340.10 - 1000
\]
Calculating the interest:
\[
\text{Interest} = 340.10
\]
### Summary of Results:
a) The final amount in the account after 6 years is approximately **$1340.10**.
b) The actual amount of interest earned is approximately **$340.10**.
\[
A = P(1 + r)^n
\]
where:
- \(A\) is the final amount in the account after \(n\) years,
- \(P\) is the principal amount (the initial deposit),
- \(r\) is the annual interest rate (in decimal form),
- \(n\) is the number of years the money is invested or borrowed.
### Given:
- \(P = 1000\)
- \(r = 5\% = 0.05\)
- \(n = 6\)
### Step a: Find the final amount in the account
Plugging in the values:
\[
A = 1000(1 + 0.05)^6
\]
Calculating \(1 + 0.05\):
\[
1 + 0.05 = 1.05
\]
Now calculating \(1.05^6\):
\[
1.05^6 \approx 1.34009564
\]
Now, multiply this by \(1000\):
\[
A = 1000 \times 1.34009564 \approx 1340.10
\]
Thus, the final amount in the account after 6 years is approximately:
\[
A \approx 1340.10
\]
### Step b: Find the actual amount of interest earned
The interest earned can be calculated as:
\[
\text{Interest} = A - P
\]
Substituting the values we have:
\[
\text{Interest} = 1340.10 - 1000
\]
Calculating the interest:
\[
\text{Interest} = 340.10
\]
### Summary of Results:
a) The final amount in the account after 6 years is approximately **$1340.10**.
b) The actual amount of interest earned is approximately **$340.10**.