The circumference of the inner circle is 88 ft. The distance between the inner circle and the outer circle is 4 ft. By how many feet is the circumference of outer circle greater than the circumference of the inner​ circle? Use StartFraction 22 Over 7 EndFraction

for pi.
4 ft
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Part 1
The circumference of outer circle is about
  
enter your response here ft greater than the circumference of the inner circle.
​(Round to the nearest tenth as​ needed.)

1 answer

To find out how much greater the circumference of the outer circle is compared to the inner circle, we first need to find the radii of both circles.

  1. Find the radius of the inner circle: The formula for the circumference \( C \) of a circle is given by:

    \[ C = 2\pi r \]

    Given that the circumference of the inner circle is 88 ft, we can set up the equation:

    \[ 88 = 2 \times \frac{22}{7} \times r_{inner} \]

    To find \( r_{inner} \), we can rearrange this equation:

    \[ r_{inner} = \frac{88}{2 \times \frac{22}{7}} = \frac{88 \times 7}{2 \times 22} = \frac{88 \times 7}{44} = 14 \text{ ft} \]

  2. Find the radius of the outer circle: The distance between the inner circle and the outer circle is 4 ft, so the radius of the outer circle is:

    \[ r_{outer} = r_{inner} + 4 = 14 + 4 = 18 \text{ ft} \]

  3. Calculate the circumference of the outer circle: Using the same formula for circumference:

    \[ C_{outer} = 2\pi r_{outer} = 2 \times \frac{22}{7} \times 18 \]

    Calculating this gives:

    \[ C_{outer} = 2 \times \frac{22}{7} \times 18 = \frac{22 \times 36}{7} = \frac{792}{7} \approx 113.14 \text{ ft} \]

  4. Calculate the difference in circumference: Now, we subtract the circumference of the inner circle from that of the outer circle.

    \[ \text{Difference} = C_{outer} - C_{inner} = \frac{792}{7} - 88 \]

    Convert 88 to a fraction with a denominator of 7:

    \[ 88 = \frac{88 \times 7}{7} = \frac{616}{7} \]

    Now compute the difference:

    \[ \text{Difference} = \frac{792}{7} - \frac{616}{7} = \frac{792 - 616}{7} = \frac{176}{7} \approx 25.14 \text{ ft} \]

  5. Round to the nearest tenth: Rounding 25.14 ft to the nearest tenth gives:

    \[ 25.1 \text{ ft} \]

Thus, the circumference of the outer circle is approximately 25.1 ft greater than the circumference of the inner circle.