To find the surface area of the net of the triangular prism, we need to calculate the area of all the faces (rectangles and triangles) of the prism.
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Areas of Rectangles:
- There are three rectangles:
- Top rectangle: Length = 10 cm, Width = 5 cm
- Middle rectangle: Length = 10 cm, Width = 5 cm
- Bottom rectangle: Length = 10 cm, Width = 5 cm
Each rectangle has an area calculated as: \[ \text{Area of one rectangle} = \text{Length} \times \text{Width} = 10 , \text{cm} \times 5 , \text{cm} = 50 , \text{cm}^2 \]
Since there are three rectangles, the total area of the rectangles is: \[ \text{Total area of rectangles} = 3 \times 50 , \text{cm}^2 = 150 , \text{cm}^2 \]
- There are three rectangles:
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Areas of Triangles:
- There are two identical triangles.
- Base of the triangle = 5 cm
- Height of the triangle = 4 cm
The area of one triangle is calculated as: \[ \text{Area of one triangle} = \frac{1}{2} \times \text{Base} \times \text{Height} = \frac{1}{2} \times 5 , \text{cm} \times 4 , \text{cm} = 10 , \text{cm}^2 \]
Since there are two triangles, the total area of the triangles is: \[ \text{Total area of triangles} = 2 \times 10 , \text{cm}^2 = 20 , \text{cm}^2 \]
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Total Surface Area:
- Now, we add the total area of the rectangles and the total area of the triangles to get the surface area of the prism: \[ \text{Total Surface Area} = \text{Total area of rectangles} + \text{Total area of triangles} = 150 , \text{cm}^2 + 20 , \text{cm}^2 = 170 , \text{cm}^2 \]
So, the surface area of the net of the triangular prism is 170 square centimeters.