Question

A table has a length of 4 1/2 feet and width of 2 1/4 feet. Find the area of the table in square feet.(1 point) Responses 8 1/8 square feet 8 and 1 eighth square feet 10 1/8 square feet 10 Start Fraction 1 over 8 end fraction square feet 6 3/4 square feet 6 Start Fraction 3 over 4 end fraction square feet 13 1/2 square feet

Answer 1

To find the area of the table, we multiply the length by the width.

The length is \( 4 \frac{1}{2} \) feet, which is equivalent to:

\[
4 \frac{1}{2} = 4 + \frac{1}{2} = \frac{8}{2} + \frac{1}{2} = \frac{9}{2} \text{ feet}
\]

The width is \( 2 \frac{1}{4} \) feet, which is equivalent to:

\[
2 \frac{1}{4} = 2 + \frac{1}{4} = \frac{8}{4} + \frac{1}{4} = \frac{9}{4} \text{ feet}
\]

Now, we can calculate the area:

\[
\text{Area} = \text{Length} \times \text{Width} = \left(\frac{9}{2}\right) \times \left(\frac{9}{4}\right)
\]

To multiply the fractions, we multiply the numerators and the denominators:

\[
\text{Area} = \frac{9 \times 9}{2 \times 4} = \frac{81}{8}
\]

Now, we can convert \(\frac{81}{8}\) to a mixed number:

\[
\frac{81}{8} = 10 \frac{1}{8} \text{ square feet}
\]

Therefore, the area of the table is \(10 \frac{1}{8}\) square feet.

The correct response is: **10 and 1 eighth square feet**.