To find the height \( h \) of the square pyramid, we can use the Pythagorean Theorem. We have the following elements:
- The slant height (\( l \)) of the pyramid is given as 25 feet.
- The length of the front base edge is 40 feet, which means the base edge length is \( b = 40 \) feet. The distance from the center of the base to the midpoint of a side (the right base edge in this case) is \( \frac{b}{2} = \frac{40}{2} = 20 \) feet.
We can form a right triangle where:
- The height \( h \) is one leg,
- The distance from the center of the base to the midpoint of the right base edge (20 feet) is the other leg,
- The slant height (25 feet) is the hypotenuse.
According to the Pythagorean Theorem: \[ l^2 = h^2 + \left(\frac{b}{2}\right)^2 \] Substituting the known values: \[ 25^2 = h^2 + 20^2 \] Calculating the squares: \[ 625 = h^2 + 400 \] Now, isolating \( h^2 \): \[ h^2 = 625 - 400 \] \[ h^2 = 225 \] Taking the square root to find \( h \): \[ h = \sqrt{225} \] \[ h = 15 \]
So the height \( h \) of the square pyramid is \( 15.0 \) feet.
Thus, the answer is:
15.0 ft.