Question
What is the volume of the sphere using 3.14 for pi and rounded to the nearest tenth? (the circle is 5 feet)
(1 point)
Responses
523.3 ft.3
523.3 ft. cubed
104.7 ft.3
104.7 ft. cubed
4,188.8 ft.3
4,188.8 ft. cubed
62.8 ft.3
62.8 ft. cubed
(1 point)
Responses
523.3 ft.3
523.3 ft. cubed
104.7 ft.3
104.7 ft. cubed
4,188.8 ft.3
4,188.8 ft. cubed
62.8 ft.3
62.8 ft. cubed
Answers
GPT-4o mini
To find the volume of a sphere, you can use the formula:
\[
V = \frac{4}{3} \pi r^3
\]
where \( V \) is the volume and \( r \) is the radius of the sphere.
Given that the diameter of the circle is 5 feet, the radius would be:
\[
r = \frac{5}{2} = 2.5 \text{ feet}
\]
Now plug in the radius and π (using 3.14) into the volume formula:
\[
V = \frac{4}{3} \times 3.14 \times (2.5)^3
\]
First, calculate \( (2.5)^3 \):
\[
(2.5)^3 = 2.5 \times 2.5 \times 2.5 = 15.625
\]
Now, substitute this back into the volume equation:
\[
V = \frac{4}{3} \times 3.14 \times 15.625
\]
Next, calculate \( \frac{4}{3} \times 3.14 \):
\[
\frac{4}{3} \times 3.14 \approx 4.1867
\]
Now, multiply this by 15.625:
\[
V \approx 4.1867 \times 15.625 \approx 65.5
\]
Hence, the approximate volume of the sphere is:
\[
V \approx 65.5 \text{ ft}^3
\]
This means none of the provided options match the calculated volume. Would you like me to double-check the answers or calculations?
\[
V = \frac{4}{3} \pi r^3
\]
where \( V \) is the volume and \( r \) is the radius of the sphere.
Given that the diameter of the circle is 5 feet, the radius would be:
\[
r = \frac{5}{2} = 2.5 \text{ feet}
\]
Now plug in the radius and π (using 3.14) into the volume formula:
\[
V = \frac{4}{3} \times 3.14 \times (2.5)^3
\]
First, calculate \( (2.5)^3 \):
\[
(2.5)^3 = 2.5 \times 2.5 \times 2.5 = 15.625
\]
Now, substitute this back into the volume equation:
\[
V = \frac{4}{3} \times 3.14 \times 15.625
\]
Next, calculate \( \frac{4}{3} \times 3.14 \):
\[
\frac{4}{3} \times 3.14 \approx 4.1867
\]
Now, multiply this by 15.625:
\[
V \approx 4.1867 \times 15.625 \approx 65.5
\]
Hence, the approximate volume of the sphere is:
\[
V \approx 65.5 \text{ ft}^3
\]
This means none of the provided options match the calculated volume. Would you like me to double-check the answers or calculations?