Question

Question

(-2, 1)
(4, 3)

Put the steps in order to find the distance between these 2 points.

(7 points)
Put responses in the correct input to answer the question. Select a response, navigate to the desired input and insert the response. Responses can be selected and inserted using the space bar, enter key, left mouse button or touchpad. Responses can also be moved by dragging with a mouse.
Step 1
Step 2
Step 3
Step 4
Step 5
Step 6
Step 7

RESPONCES:
Determine the vertical side (2 units) and horizontal side (6 units) lenghts by counting on the grid (be careful of the scale), or using the vertical coordinates (3 to 1) and horizontal coordinates (-2 to 4).
4 + 36 = c^(2)
\sqrt{40} = \sqrt{c^(2)}
Draw a right triangle by dropping a vertical side and a horizontal side.
\sqrt{40} is between \sqrt{36} and \sqrt{49}, so between 6 and 7 - closer to 6, so about 6.3 units.
40 = c^(2)
Use the Pythagorean Theorem for right triangles to determine the diagonal length: 2^(2) + 6^(2) = c^(2)

Answer 1

To find the distance between the two points (-2, 1) and (4, 3), follow these steps in the correct order:

Step 1: Draw a right triangle by dropping a vertical side and a horizontal side.

Step 2: Determine the vertical side (2 units) and horizontal side (6 units) lengths by counting on the grid (be careful of the scale), or using the vertical coordinates (3 to 1) and horizontal coordinates (-2 to 4).

Step 3: Use the Pythagorean Theorem for right triangles to determine the diagonal length: \( 2^2 + 6^2 = c^2 \).

Step 4: \( 4 + 36 = c^2 \).

Step 5: \( 40 = c^2 \).

Step 6: \( \sqrt{40} = \sqrt{c^2} \).

Step 7: \( \sqrt{40} \) is between \( \sqrt{36} \) and \( \sqrt{49} \), so between 6 and 7 - closer to 6, so about 6.3 units.