A circus tent is in the shape of a square pyramid. Each edge of the square base is 20 m and its slant height is 13.5 m. Find the height of the tent. Round the answer to the nearest tenth.(1 point)

Responses

24.1 cm
24.1 cm

16.8 m 
16.8 m 

9.1 m 
9.1 m 

14.8 cm

1 answer

To find the height of the pyramid tent, we can use the relationship between the slant height, the height of the pyramid, and the half of the base edge length.

  1. First, let's find the half of the base edge length. Since the edge of the square base is 20 m, half of this length is: \[ \frac{20}{2} = 10 \text{ m} \]

  2. Now, we can apply the Pythagorean theorem. In a right triangle formed by the height of the pyramid (h), the half base edge (10 m), and the slant height (13.5 m), we have: \[ h^2 + 10^2 = 13.5^2 \]

  3. Calculate \(10^2\) and \(13.5^2\): \[ 10^2 = 100 \] \[ 13.5^2 = 182.25 \]

  4. Plug these values into the equation: \[ h^2 + 100 = 182.25 \]

  5. Solve for \(h^2\): \[ h^2 = 182.25 - 100 = 82.25 \]

  6. Now take the square root to find \(h\): \[ h = \sqrt{82.25} \approx 9.1 \text{ m} \]

Therefore, the height of the tent is approximately 9.1 m. The correct response is:

9.1 m