To find \( f(2x + 1) \) when \( f(x) = x^2 + 9 \), we first need to substitute \( 2x + 1 \) into the function \( f \).
- Start with \( f(x) = x^2 + 9 \).
- Substitute \( 2x + 1 \) for \( x \) in \( f(x) \):
\[ f(2x + 1) = (2x + 1)^2 + 9 \]
- Expand \( (2x + 1)^2 \):
\[ (2x + 1)^2 = 4x^2 + 4x + 1 \]
- Now substitute this back into the function:
\[ f(2x + 1) = 4x^2 + 4x + 1 + 9 = 4x^2 + 4x + 10 \]
- Now plug in \( x = 2 \):
\[ f(2(2) + 1) = f(4 + 1) = f(5) \]
- Calculate \( f(5) \):
\[ f(5) = 5^2 + 9 = 25 + 9 = 34 \]
So, the correct transformation of \( f(2x + 1) \) evaluated at \( x = 2 \) gives us \( 34 \).
The answer is:
34