To transform the equation \( 3y + 3x = 9 \) into slope-intercept form \( y = mx + b \), follow these steps:
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Start with the original equation: \[ 3y + 3x = 9 \]
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Isolate the \( y \) term: Subtract \( 3x \) from both sides: \[ 3y = 9 - 3x \]
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Divide every term by 3 to solve for \( y \): \[ y = \frac{9}{3} - \frac{3x}{3} \] This simplifies to: \[ y = 3 - x \]
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Rewrite for slope-intercept form: To express it in the standard form \( y = mx + b \), we can rearrange: \[ y = -x + 3 \]
Now, the equation in slope-intercept form is: \[ y = -x + 3 \]
- Here, the slope \( m = -1 \) and the y-intercept \( b = 3 \).
Final answer: \[ y = -x + 3 \]
Steps shown:
- \( 3y + 3x = 9 \)
- \( 3y = 9 - 3x \)
- \( y = 3 - x \)
- \( y = -x + 3 \)
(2 points: 1 for the correct answer and 1 for showing steps of work.)