What is the slope (m)

of a line perpendicular to the line y=−4/3x+2
?(1 point)
m=

1 answer

To find the slope of a line that is perpendicular to the given line \( y = -\frac{4}{3}x + 2 \), we need to determine the negative reciprocal of the slope of the given line.

The slope of the given line is \( -\frac{4}{3} \).

The negative reciprocal of \( -\frac{4}{3} \) is calculated as follows:

  1. Take the reciprocal: The reciprocal of \( -\frac{4}{3} \) is \( -\frac{3}{4} \).
  2. Change the sign: The negative reciprocal is \( \frac{3}{4} \).

Thus, the slope \( m \) of a line perpendicular to the given line is:

\[ m = \frac{3}{4} \]