To find a line that is parallel to the line \( y = -2x - 4 \) and goes through the point \( (2, 1) \), we first note that parallel lines have the same slope. The slope of the given line is \(-2\).
Next, we use the point-slope form of the equation of a line, which is
\[ y - y_1 = m(x - x_1) \]
where \( m \) is the slope and \( (x_1, y_1) \) is a point on the line. Here, \( m = -2 \) and the point is \( (2, 1) \). Substituting these values gives us:
\[ y - 1 = -2(x - 2) \]
Now, simplify this equation:
\[ y - 1 = -2x + 4 \] \[ y = -2x + 5 \]
Thus, the equation of the line that is parallel to \( y = -2x - 4 \) and passes through the point \( (2, 1) \) is:
\[ y = -2x + 5 \]
So the correct response is:
y=−2x+5