Question
Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.
Show that sin(x+π)=−sin x
Show all of your work.
Show that sin(x+π)=−sin x
Show all of your work.
Answers
Answered by
GPT-4o mini
To show that \(\sin(x + \pi) = -\sin x\), we will use the sine addition formula and properties of the sine function.
### Step 1: Apply the Sine Addition Formula
The sine addition formula states that:
\[
\sin(a + b) = \sin a \cos b + \cos a \sin b
\]
Let \(a = x\) and \(b = \pi\). Then we can rewrite the expression as:
\[
\sin(x + \pi) = \sin x \cos \pi + \cos x \sin \pi
\]
### Step 2: Substitute Values of \(\cos \pi\) and \(\sin \pi\)
We know that:
\[
\cos \pi = -1 \quad \text{and} \quad \sin \pi = 0
\]
Substituting these values into the equation gives:
\[
\sin(x + \pi) = \sin x \cdot (-1) + \cos x \cdot 0
\]
### Step 3: Simplify the Expression
This simplifies to:
\[
\sin(x + \pi) = -\sin x + 0
\]
Thus, we have:
\[
\sin(x + \pi) = -\sin x
\]
### Conclusion
We have shown that:
\[
\sin(x + \pi) = -\sin x
\]
This completes the proof.
### Step 1: Apply the Sine Addition Formula
The sine addition formula states that:
\[
\sin(a + b) = \sin a \cos b + \cos a \sin b
\]
Let \(a = x\) and \(b = \pi\). Then we can rewrite the expression as:
\[
\sin(x + \pi) = \sin x \cos \pi + \cos x \sin \pi
\]
### Step 2: Substitute Values of \(\cos \pi\) and \(\sin \pi\)
We know that:
\[
\cos \pi = -1 \quad \text{and} \quad \sin \pi = 0
\]
Substituting these values into the equation gives:
\[
\sin(x + \pi) = \sin x \cdot (-1) + \cos x \cdot 0
\]
### Step 3: Simplify the Expression
This simplifies to:
\[
\sin(x + \pi) = -\sin x + 0
\]
Thus, we have:
\[
\sin(x + \pi) = -\sin x
\]
### Conclusion
We have shown that:
\[
\sin(x + \pi) = -\sin x
\]
This completes the proof.