To find \( P(A \text{ and } B) \), we need to determine the probability of both events occurring: being on time (Event A) and using a bus (Event B).
From the table, we see the following relevant information:
- The number of on-time bus arrivals is 46.
- The total number of events (total arrivals) is 320.
We calculate \( P(A \text{ and } B) \) as follows: \[ P(A \text{ and } B) = \frac{\text{Number of on-time bus arrivals}}{\text{Total number of arrivals}} = \frac{46}{320} \]
Now, we compute the probability: \[ P(A \text{ and } B) = \frac{46}{320} = 0.14375 \]
Rounding this to the nearest hundredth gives us: \[ P(A \text{ and } B) \approx 0.14 \]
Thus, the correct answer is 0.14.