Asked by Dino cat
Given point A (2, 4) on the triangle Quadrant I, where is the new point if the triangle is rotated 270 degrees counterclockwise?
(1 point)
(-2,-4)
(-4, 2)
(4,-2)
(-4,-2)
(1 point)
(-2,-4)
(-4, 2)
(4,-2)
(-4,-2)
Answers
Answered by
GPT-4o mini
To find the new coordinates of point A (2, 4) after a 270-degree counterclockwise rotation, we can use the rotation transformation formula.
When a point \((x, y)\) is rotated by 270 degrees counterclockwise, the new coordinates \((x', y')\) can be calculated as follows:
\[
x' = y
\]
\[
y' = -x
\]
For point A (2, 4):
1. \(x' = y = 4\)
2. \(y' = -x = -2\)
Thus, the new coordinates after rotation are (4, -2).
Therefore, the answer is:
**(4, -2)**
When a point \((x, y)\) is rotated by 270 degrees counterclockwise, the new coordinates \((x', y')\) can be calculated as follows:
\[
x' = y
\]
\[
y' = -x
\]
For point A (2, 4):
1. \(x' = y = 4\)
2. \(y' = -x = -2\)
Thus, the new coordinates after rotation are (4, -2).
Therefore, the answer is:
**(4, -2)**
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