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Given point A (2, 4) on the triangle in Quadrant I, where is the new point if the triangle is rotated 90 degrees counterclockwise?

(1 point)

(-2,-4)

(4,-2)

(-4,-2)

(-4, 2)

1 answer

To rotate a point 90 degrees counterclockwise around the origin, you can use the transformation rule:

If the original point is (x, y), then after a 90 degrees counterclockwise rotation, the new coordinates (x', y') will be:

\[ x' = -y \] \[ y' = x \]

For point A (2, 4):

  1. \( x' = -y = -4 \)
  2. \( y' = x = 2 \)

So, after the rotation, the new point A' is (-4, 2).

Therefore, the new point is (-4, 2).