Let's address each question one by one:
Question 1 A)
To identify a point that generates the parabola for the quadratic equation \( y = -6x^2 + 3x + 8 \), we can substitute the given x-values into the equation and see if any of the responses yield results.
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For \( (-6, 8) \): \[ y = -6(-6)^2 + 3(-6) + 8 = -6(36) - 18 + 8 = -216 - 18 + 8 = -226 \quad (\text{not a solution}) \]
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For \( (-3, -55) \): \[ y = -6(-3)^2 + 3(-3) + 8 = -6(9) - 9 + 8 = -54 - 9 + 8 = -55 \quad (\text{is a solution}) \]
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For \( (-6, 206) \): \[ y = -6(-6)^2 + 3(-6) + 8 = -226 \quad (\text{not a solution}) \]
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For \( (-3, 323) \): \[ y = -6(-3)^2 + 3(-3) + 8 = -55 \quad (\text{not a solution}) \]
Correct Response: \( (-3, -55) \) is a point that generates the parabola.
Question 2 A)
Based on the values given, we want to identify the high or low point (vertex) of the parabola represented by \( y = -6x^2 + 3x + 8 \).
From the values:
- At \( x = -1 \), \( y = -1 \)
- At \( x = -0.75 \), \( y = 2.375 \)
- At \( x = -0.5 \), \( y = 5 \)
- At \( x = -0.25 \), \( y = 8 \)
- At \( x = 0.25 \), \( y = 8.375 \)
- At \( x = 0.5 \), \( y = 0.75 \)
- At \( x = 1 \), \( y = 5 \)
The highest point here is \( (0.25, 8.375) \).
Correct Response: \( (0.25, 8.375) \) is the high point on the parabola.
Question 3 A)
To identify a zero (or x-intercept) on the graph, we need points where \( y = 0 \). Among the provided options, we would typically need to examine the graph to check if any given points are x-intercepts. Given the choices, if there is a point where \( y = 0 \), it may be \( x = 1.5 \) or other options.
Without the graph, the best approach here is to point out a well-known basic property of parabolas.
If you're provided with a particular graph showing x-intercepts, you need to select the correctly identified x-intercept from there.
Question 4 A)
Again, without the image of the graph, I can't provide the exact coordinates of the vertex. If you have identified the vertex of the parabola using \( y = ax^2 + bx + c \) or interpret it from the graph, you would select the matching point among the options presented.
Typically, the vertex of a parabola described by \( ax^2 + bx + c \) can be found using the formula \( x = -\frac{b}{2a} \). Plugging the values in gives you the x-coordinate, and substituting that x back into the equation gives you the y-coordinate.
Question 5 A)
Without an image to refer to, the correct response would typically be based on the properties of the graph based on choices.
From typical properties:
- If the vertex is the only x-intercept, that indicates it touches the x-axis at that point.
- The vertex gives the highest or lowest point, depending on whether it opens upwards or downwards.
Choose the statement that best reflects the relationship depicted in the available graph.
Correct Response: Depends entirely on the graphical details provided.
If you have access to the graphs, I can help interpret them based on your observations.