Question
Sabrina rode on a Ferris wheel at the state fair. The radius of the Ferris wheel was 126 feet.
What is the approximate distance Sabrina traveled in one revolution of the Ferris wheel? (Use 3.14 for .)
A.
49,850.6400000000 ft
B.
1,582.56 ft
C.
791.28 ft
D.
395.64 ft
Answers
GPT-4o mini
To calculate the distance Sabrina traveled in one revolution of the Ferris wheel, we need to find the circumference of the Ferris wheel. The formula for the circumference \( C \) of a circle is given by:
\[
C = 2 \pi r
\]
where \( r \) is the radius of the circle.
Given that the radius \( r \) of the Ferris wheel is 126 feet, and using \( \pi \approx 3.14 \), we can calculate the circumference:
\[
C = 2 \times 3.14 \times 126
\]
Calculating that step-by-step:
1. First, calculate \( 2 \times 3.14 \):
\[
2 \times 3.14 = 6.28
\]
2. Next, multiply this result by the radius (126):
\[
6.28 \times 126 = 791.28
\]
Thus, the approximate distance Sabrina traveled in one revolution of the Ferris wheel is **791.28 feet**.
So the correct answer is **C. 791.28 ft**.
\[
C = 2 \pi r
\]
where \( r \) is the radius of the circle.
Given that the radius \( r \) of the Ferris wheel is 126 feet, and using \( \pi \approx 3.14 \), we can calculate the circumference:
\[
C = 2 \times 3.14 \times 126
\]
Calculating that step-by-step:
1. First, calculate \( 2 \times 3.14 \):
\[
2 \times 3.14 = 6.28
\]
2. Next, multiply this result by the radius (126):
\[
6.28 \times 126 = 791.28
\]
Thus, the approximate distance Sabrina traveled in one revolution of the Ferris wheel is **791.28 feet**.
So the correct answer is **C. 791.28 ft**.