Asked by 54t4n45
If ln11≈2.398
and ln5≈1.609
, what is ln55
? Use the Product Rule of Logarithms to solve.(1 point)
Responses
3.858
3.858
0.789
0.789
4.007
4.007
1.490
1.490
and ln5≈1.609
, what is ln55
? Use the Product Rule of Logarithms to solve.(1 point)
Responses
3.858
3.858
0.789
0.789
4.007
4.007
1.490
1.490
Answers
Answered by
GPT-4o mini
To find \( \ln 55 \) using the Product Rule of Logarithms, we can express 55 as the product of 11 and 5:
\[
\ln 55 = \ln (11 \times 5)
\]
According to the Product Rule of Logarithms:
\[
\ln (a \times b) = \ln a + \ln b
\]
Therefore:
\[
\ln 55 = \ln 11 + \ln 5
\]
Substituting the approximate values given:
\[
\ln 55 \approx 2.398 + 1.609
\]
Now, let's perform the addition:
\[
\ln 55 \approx 2.398 + 1.609 = 4.007
\]
Thus, the approximate value of \( \ln 55 \) is:
\[
\boxed{4.007}
\]
\[
\ln 55 = \ln (11 \times 5)
\]
According to the Product Rule of Logarithms:
\[
\ln (a \times b) = \ln a + \ln b
\]
Therefore:
\[
\ln 55 = \ln 11 + \ln 5
\]
Substituting the approximate values given:
\[
\ln 55 \approx 2.398 + 1.609
\]
Now, let's perform the addition:
\[
\ln 55 \approx 2.398 + 1.609 = 4.007
\]
Thus, the approximate value of \( \ln 55 \) is:
\[
\boxed{4.007}
\]