Which of the following uses the properties of logarithms to correctly evaluate log1023

?(1 point) only use answers ive given

Responses

log1023=23
logarithm 10 superscript 23 baseline equals 23

log1023=−23
logarithm 10 superscript 23 baseline equals negative 23

log1023=1023
logarithm 10 superscript 23 baseline equals 10 superscript 23 baseline

log1023=10−23

1 answer

To evaluate \( \log_{10} 23 \), we can use the definition of the logarithm. The logarithm \( \log_{10} 23 \) represents the exponent to which the base (10) must be raised to produce the number 23.

The possible responses you've given don't correctly evaluate \( \log_{10} 23 \) based on the properties of logarithms. Here's what each option states:

  1. \( \log_{10} 23 = 23 \): This is incorrect. \( 10^{23} \) is much larger than 23.

  2. \( \log_{10} 23 = -23 \): This is also incorrect. A logarithm cannot be negative if the argument (23) is greater than 1.

  3. \( \log_{10} 23 = 1023 \): This is incorrect. This implies \( 10^{1023} \) which is vastly larger than 23.

  4. \( \log_{10} 23 = 10^{-23} \): This implies that \( 10^{-23} \) equals 23, which is not true.

None of the options you provided correctly evaluate \( \log_{10} 23 \). The correct value can be approximated using a calculator, but based on the choices given, there’s no valid response. A correct evaluation would yield a value that is between 1 and 2 since \( 10^1 = 10 \) and \( 10^2 = 100\), and 23 lies between these two powers.

Thus, the answer is that none of the provided statements accurately represent \( \log_{10} 23\).