Use the image to answer the question.

An illustration shows a rectangle of length as whole number 6 start fraction 1 over 2 end fraction centimeters and width as whole number 4 start fraction 1 over 2 end fraction centimeters. The lengths are horizontally positioned and widths are vertically positioned.

Byron calculated the area of the rectangle as 22 square centimeters. What is the error in his reasoning and what is the correct answer?

(1 point)
Responses

Byron found the perimeter of the rectangle. The correct area is 24 1/4
square centimeters.
Byron found the perimeter of the rectangle. The correct area is 24 Start Fraction 1 over 4 End Fraction square centimeters.

Byron found the perimeter of the rectangle. The correct area is 29 1/4
square centimeters.
Byron found the perimeter of the rectangle. The correct area is 29 Start Fraction 1 over 4 End Fraction square centimeters.

Byron found the perimeter of the rectangle. The correct area is 11 square centimeters.
Byron found the perimeter of the rectangle. The correct area is 11 square centimeters.

Byron found the perimeter of the rectangle. The correct area is 22 square centimeters.
Byron found the perimeter of the rectangle. The correct area is 22 square centimeters.
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1 answer

To find the area of the rectangle, we can use the formula for the area of a rectangle, which is:

\[ \text{Area} = \text{Length} \times \text{Width} \]

The given dimensions of the rectangle are:

  • Length: \(6 \frac{1}{2}\) centimeters, which can be converted to an improper fraction: \[ 6 \frac{1}{2} = 6 + \frac{1}{2} = \frac{12}{2} + \frac{1}{2} = \frac{13}{2} \text{ cm} \]

  • Width: \(4 \frac{1}{2}\) centimeters, which can also be converted to an improper fraction: \[ 4 \frac{1}{2} = 4 + \frac{1}{2} = \frac{8}{2} + \frac{1}{2} = \frac{9}{2} \text{ cm} \]

Now, we can calculate the area:

\[ \text{Area} = \left(\frac{13}{2}\right) \times \left(\frac{9}{2}\right) = \frac{13 \times 9}{2 \times 2} = \frac{117}{4} \text{ square centimeters} \]

Now, to convert \(\frac{117}{4}\) into a mixed number:

\[ 117 \div 4 = 29 \quad \text{(remainder 1)} \] Thus, \[ \frac{117}{4} = 29 \frac{1}{4} \text{ square centimeters} \]

Byron calculated the area as 22 square centimeters, which is incorrect. He likely made a mistake by not using the correct dimensions or the method of calculation.

So, the correct choice is:

Byron found the perimeter of the rectangle. The correct area is 29 Start Fraction 1 over 4 End Fraction square centimeters.