Expand the logarithm ln(13x) .(1 point)Responsesln(13−x)l n left parenthesis 13 minus x right parenthesis13−x13 minus xln13lnxStart Fraction l n 13 over l n x End Fractionln13−lnx

Answer 1

To expand the logarithm \( \ln(13x) \), we can use the properties of logarithms. Specifically, the property that states \( \ln(ab) = \ln(a) + \ln(b) \).

Here, we have:

\[ \ln(13x) = \ln(13) + \ln(x) \]

So the expanded form is:

\[ \ln(13) + \ln(x) \]

Thus, the correct response is:

\[ \ln(13) + \ln(x) \]

If you were given multiple-choice options, the correct answer from the ones listed would be:

\(\ln 13 + \ln x\) (or equivalent to that representation if formatted differently).