Calian wants to construct a viable argument to justify that logbb=1 for b>0 and b≠1. Fill in the blanks to help him construct his argument.(2 points)Any positive number raised to the power  is equal to itself. Written as an equation, this means that $$ for any positive base. This equation is equivalent to the logarithmic equation $$. Therefore, it must be true that logbb=1 for any positive base that is not equal to 1.

1 answer

Any positive number raised to the power 1 is equal to itself. Written as an equation, this means that \( b^1 = b \) for any positive base. This equation is equivalent to the logarithmic equation \( \log_b b = 1 \). Therefore, it must be true that \( \log_b b = 1 \) for any positive base that is not equal to 1.