There is a line that includes the point (–6,–3) and has a slope of 1/7

. What is its equation in point-slope form?

1 answer

To write the equation of a line in point-slope form, you can use the formula:

\[ y - y_1 = m(x - x_1) \]

where \( (x_1, y_1) \) is a point on the line, and \( m \) is the slope.

In this case, you have the point \((-6, -3)\) and the slope \(m = \frac{1}{7}\).

Plugging in these values:

\[ y - (-3) = \frac{1}{7}(x - (-6)) \]

This simplifies to:

\[ y + 3 = \frac{1}{7}(x + 6) \]

So, the equation of the line in point-slope form is:

\[ y + 3 = \frac{1}{7}(x + 6) \]