Question

There is a line that includes the point (–6,–3) and has a slope of 1/7
. What is its equation in point-slope form?

Answer 1

To write the equation of a line in point-slope form, you can use the formula:

\[
y - y_1 = m(x - x_1)
\]

where \( (x_1, y_1) \) is a point on the line, and \( m \) is the slope.

In this case, you have the point \((-6, -3)\) and the slope \(m = \frac{1}{7}\).

Plugging in these values:

\[
y - (-3) = \frac{1}{7}(x - (-6))
\]

This simplifies to:

\[
y + 3 = \frac{1}{7}(x + 6)
\]

So, the equation of the line in point-slope form is:

\[
y + 3 = \frac{1}{7}(x + 6)
\]